Capacitance and Dielectrics — 50 MCQs
50 MCQs on capacitance, parallel-plate capacitor, series and parallel combinations, energy stored, and dielectric effects.
-
1. A capacitor is a device used to store:
easyExplanation: A capacitor stores electric charge on its plates and electrical potential energy in the electric field between them. -
2. The SI unit of capacitance is:
easyExplanation: Capacitance is measured in farads (F), where 1 F = 1 C/V. -
3. Capacitance is defined as:
easyExplanation: By definition, capacitance C = ΔQ/ΔV, the amount of charge stored per unit increase in potential difference. -
4. One farad is equal to:
easyExplanation: From C = Q/V, one farad is one coulomb per volt. -
5. On a Q–V graph for a capacitor, the gradient of the straight line represents:
easyExplanation: Since Q = CV, the slope of Q against V is ΔQ/ΔV = C. -
6. Practical capacitor values are most commonly expressed in:
easyExplanation: A farad is large, so practical capacitors are commonly specified in μF, nF, or pF. -
7. Which of the following is NOT a typical use of a capacitor?
mediumExplanation: Capacitors store and release charge, filter, time, and couple signals; they do not amplify current gain in a transistor. -
8. The two plates of a charged capacitor carry:
easyExplanation: One plate carries +Q and the other −Q with equal magnitude. -
9. A capacitor blocks:
easyExplanation: In steady state, a capacitor blocks DC but allows AC to pass, depending on frequency and circuit conditions. -
10. If the potential difference across a capacitor is doubled, the charge stored (assuming constant C):
easyExplanation: Since Q = CV, charge is directly proportional to potential difference when capacitance is constant. -
11. The capacitance of a capacitor depends on:
easyExplanation: Capacitance depends on geometry and dielectric, not on Q or V for a given capacitor. -
12. A dielectric material is best described as:
easyExplanation: Dielectrics are insulating materials whose molecules polarize when placed in an electric field. -
13. If ΔQ = 4 μC produces ΔV = 2 V across a capacitor, its capacitance is:
easyExplanation: C = ΔQ/ΔV = 4 μC / 2 V = 2 μF. -
14. A capacitor with a steeper Q–V graph compared to another indicates:
mediumExplanation: A steeper slope means more charge is stored per volt, so capacitance is higher. -
15. Which symbol correctly represents permittivity of free space?
easyExplanation: ε₀ is the permittivity of free space, while εᵣ is the relative permittivity. -
16. The formula for the capacitance of a parallel plate capacitor with vacuum between the plates is:
easyExplanation: For a parallel plate capacitor, C = ε₀A/d. -
17. In the derivation of C = ε₀A/d, which law is applied to find the electric field between the plates?
mediumExplanation: Gauss’s law gives the field between plate sheets, leading to E = σ/ε₀. -
18. If the plate area of a parallel plate capacitor is doubled while separation remains constant, the capacitance:
easyExplanation: Capacitance is proportional to area A, so doubling A doubles C. -
19. If the plate separation of a parallel plate capacitor is halved while area remains constant, the capacitance:
easyExplanation: Capacitance is inversely proportional to separation d, so halving d doubles C. -
20. The electric field between the plates of a charged parallel plate capacitor (vacuum) is given by:
mediumExplanation: Each plate contributes σ/2ε₀, and these add between the plates to give σ/ε₀. -
21. Outside the plates of an ideal parallel plate capacitor, the net electric field is:
mediumExplanation: The fields outside are equal and opposite and cancel each other, giving zero net field. -
22. A parallel plate capacitor has plates of area 0.01 m² separated by 2 mm in vacuum. Its capacitance is approximately: (ε₀ = 8.85 × 10⁻¹² F/m)
mediumExplanation: C = ε₀A/d = (8.85×10⁻¹² × 0.01)/(2×10⁻³) = 4.43×10⁻¹¹ F, about 44 pF. -
23. Which graph correctly represents C plotted against 1/d for a parallel plate capacitor (A constant)?
mediumExplanation: With A fixed, C = ε₀A(1/d), so C is directly proportional to 1/d and gives a straight line through the origin. -
24. Doubling both the plate area and the plate separation of a parallel plate capacitor leaves the capacitance:
easyExplanation: C = ε₀A/d; if both A and d double, the ratio A/d does not change. -
25. If a parallel plate capacitor's area is tripled and its separation is also tripled, the new capacitance compared to the original is:
easyExplanation: Since both A and d scale by the same factor, A/d remains constant and C is unchanged. -
26. For capacitors connected in series, which quantity is the same across each capacitor?
easyExplanation: In series, the same charge appears on each capacitor because charge is conserved in the chain. -
27. For capacitors connected in parallel, which quantity is the same across each capacitor?
easyExplanation: Each capacitor in parallel is connected across the same two points, so the potential difference is common. -
28. The equivalent capacitance of capacitors in series is:
easyExplanation: For series, 1/C_s = Σ(1/C_i), and C_s is always less than the smallest capacitance. -
29. The equivalent capacitance of capacitors in parallel is:
easyExplanation: Parallel adds capacitance: C_p = C_1 + C_2 + ... . It is always greater than the largest individual value. -
30. Two capacitors of 4 μF and 4 μF are connected in series. The equivalent capacitance is:
easyExplanation: For equal capacitors in series, C_s = C/n = 4/2 = 2 μF. -
31. Two capacitors of 4 μF and 4 μF are connected in parallel. The equivalent capacitance is:
easyExplanation: In parallel, C_p = 4 + 4 = 8 μF. -
32. Three identical capacitors of capacitance C are connected in series. The equivalent capacitance is:
easyExplanation: 1/C_s = 1/C + 1/C + 1/C = 3/C, so C_s = C/3. -
33. Two capacitors, 2 μF and 3 μF, are connected in series across a 10 V battery. The charge on each capacitor is:
mediumExplanation: The series equivalent is 1.2 μF, so Q = C_sV = 1.2×10 = 12 μC on each capacitor. -
34. Two capacitors, 2 μF and 3 μF, connected in parallel across a 10 V battery. The total charge supplied is:
mediumExplanation: C_p = 2 + 3 = 5 μF, so Q = C_pV = 5×10 = 50 μC. -
35. A 6 μF capacitor is in series with a parallel combination of 3 μF and 3 μF. The total equivalent capacitance is:
mediumExplanation: The parallel part is 6 μF, and in series with another 6 μF gives C = 3 μF. -
36. Four identical capacitors of 8 μF are connected: two in series, and this series pair is connected in parallel with the other two capacitors also in series. The total capacitance is:
mediumExplanation: Each series pair gives 4 μF, and two such branches in parallel give 8 μF total. -
37. In a series combination of unequal capacitors, the capacitor with the smallest capacitance:
mediumExplanation: Since Q is same in series and V = Q/C, a smaller capacitance has larger voltage across it. -
38. In a parallel combination of unequal capacitors, the capacitor with the largest capacitance:
easyExplanation: With common voltage V, Q = CV, so the largest capacitance stores the largest charge. -
39. The energy stored in a charged capacitor is given by the area under which graph?
easyExplanation: The area under the Q–V graph gives the work done in charging, equal to the stored energy. -
40. The correct expression for energy stored in a capacitor is:
easyExplanation: The factor ½ appears because the voltage rises gradually from 0 to V during charging. -
41. Why is E = QV (without the factor ½) incorrect for a capacitor?
mediumExplanation: The capacitor is charged from zero to final voltage, so V is not constant across the process. -
42. A 5 μF capacitor is charged to 100 V. The energy stored is:
mediumExplanation: E = ½CV² = ½×5×10⁻⁶×(100)² = 0.025 J. -
43. If the potential difference across a capacitor is doubled, the energy stored:
easyExplanation: Since E = ½CV², energy is proportional to V², so doubling V quadruples E. -
44. A capacitor stores charge 8 μC at 4 V. The energy stored is:
mediumExplanation: E = ½QV = ½×8×10⁻⁶×4 = 16 μJ. -
45. Two capacitors of equal capacitance C are first connected in series and then in parallel across the same voltage V. The ratio of energy stored (series : parallel) is:
mediumExplanation: Series equivalent is C/2 and parallel equivalent is 2C, giving E_s : E_p = 1 : 4. -
46. When a dielectric is placed in an external electric field, its molecules become:
easyExplanation: The field displaces or aligns charges within each molecule, producing polarization. -
47. When a dielectric slab completely fills the gap of a parallel plate capacitor, the capacitance becomes:
easyExplanation: Capacitance rises to C = εᵣ ε₀ A/d = εᵣ C₀. -
48. An isolated, charged parallel plate capacitor (disconnected from the battery) has a dielectric inserted between its plates. Which of the following remains constant?
mediumExplanation: With no path for charge to flow, Q remains fixed while V and E reduce and C increases. -
49. A parallel plate capacitor remains connected to a battery while a dielectric is inserted. Which quantity stays constant?
mediumExplanation: The battery maintains a fixed voltage V, so as C increases, Q also increases. -
50. The bound (induced) charge that appears on the surface of a dielectric in an external field arises because:
hardExplanation: A dielectric remains electrically neutral overall; the surface charge comes from molecular polarization, not free charge flow.